University of Engineering and Technology (UET) Lahore

نشط

University of Engineering and Technology Lahore Engineering College Admission Test (ECAT) Fall 2026

Engineering and Technology Admissions

الأسئلة

المدة

درجة النجاح

50%

خصم الإجابة الخاطئة

-0.25

الفئة

University of Engineering and Technology (UET) Lahore

رقم القضية

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Exam Questions

±4

±8

±16

ExplanationFor equal roots, the discriminant D = b² - 4ac = 0. Here, (-k)² - 4(1)(16) = 0, so k² = 64, k = ±8.

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5/3

3/5

ExplanationUsing the fundamental limit theorem lim(θ→0) sin(θ)/θ = 1, multiplying by 5/5 gives (5/3) * lim(x→0) (sin(5x)/5x) = 5/3.

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1/4

3/4

1/2

2/3

ExplanationUsing the sum formula S = a / (1 - r), we have 12 = 3 / (1 - r), which simplifies to 1 - r = 3/12 = 1/4, so r = 3/4.

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2e^(2x)ln(x) + e^(2x)/x

e^(2x)ln(x) + e^(2x)/x

2e^(2x)ln(x) + x*e^(2x)

e^(2x)/x

ExplanationUsing the product rule (uv)' = u'v + uv', where u = e^(2x) and v = ln(x), we get 2e^(2x)ln(x) + e^(2x)(1/x).

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32/3

16/3

8/3

64/3

ExplanationArea = integral from -2 to 2 of (4 - x^2) dx = [4x - x^3/3] from -2 to 2 = (8 - 8/3) - (-8 + 8/3) = 16/3 + 16/3 = 32/3.

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-2

-10

ExplanationThe determinant of [[a, b], [c, d]] is ad - bc. Thus, (1*4) - (2*3) = 4 - 6 = -2.

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f(x) = x^3

f(x) = sin(x)

f(x) = x^2 + cos(x)

f(x) = x + 1

ExplanationA function is even if f(-x) = f(x). For x^2 + cos(x), (-x)^2 + cos(-x) = x^2 + cos(x).

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3x + 4y = 25

4x + 3y = 25

3x + 4y = 5

x + y = 7

ExplanationThe equation of tangent at (x1, y1) to circle x² + y² = r² is xx1 + yy1 = r². Substituting (3, 4) and 25, we get 3x + 4y = 25.

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Explanation(f ∘ g)(x) = f(g(x)) = f(x²). Substituting x=2, g(2)=4. Then f(4) = 3(4) - 5 = 7.

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45,360

90,720

362,880

22,680

ExplanationTotal letters = 9. Repetitions: M=2, T=2, E=2. Permutations = 9! / (2! * 2! * 2!) = 362,880 / 8 = 45,360.

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University of Engineering and Technology Lahore Engineering College Admission Test (ECAT) Fall 2026 paper pattern infographic: subject-wise question distribution across 50 MCQs, 2h duration, −0.25 negative marking per wrong answer — University of Engineering and Technology Lahore Engineering College Admission Test (ECAT) Fall 2026 — subject-wise question distribution, per the official syllabus

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University of Engineering and Technology Lahore Engineering College Admission Test (ECAT) Fall 2026 — Frequently Asked Questions

How many questions are in the University of Engineering and Technology Lahore Engineering College Admission Test (ECAT) Fall 2026 practice test?

This practice test currently has 50 MCQs, and every question includes the correct answer with an explanation.

How long is the University of Engineering and Technology Lahore Engineering College Admission Test (ECAT) Fall 2026 mock test?

The full mock runs for 2h under real exam timing, just like the actual paper.

Is there negative marking in this test?

This simulation applies negative marking of −0.25 per wrong answer. Always confirm the official rule in the advertisement for the real exam.

What score do I need to pass?

The passing score in this simulation is 50%, but for competitive merit you should aim well above it.

Is University of Engineering and Technology Lahore Engineering College Admission Test (ECAT) Fall 2026 preparation free on PrepPro?

Yes — the questions, explanations and full timed mock test are all free. You can start practising right from this page.

How do I prepare for University of Engineering and Technology Lahore Engineering College Admission Test (ECAT) Fall 2026 online?

Practise the syllabus-based MCQs, then sit the full timed mock test and use your result analytics to find and repeat weak topics — all of it starts free from this page.

Can I retake the University of Engineering and Technology Lahore Engineering College Admission Test (ECAT) Fall 2026 mock test?

Yes — you can retake the mock test as many times as you like; every attempt is saved separately in your history so you can track your improvement.

Is the University of Engineering and Technology Lahore Engineering College Admission Test (ECAT) Fall 2026 mock test available in Urdu?

Yes — this entire page has an Urdu mirror under /ur, and the preparation content is available in both English and Urdu.

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